Optimal. Leaf size=81 \[ \frac{2 (-a B e-A b e+2 b B d)}{3 e^3 (d+e x)^{3/2}}-\frac{2 (b d-a e) (B d-A e)}{5 e^3 (d+e x)^{5/2}}-\frac{2 b B}{e^3 \sqrt{d+e x}} \]
[Out]
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Rubi [A] time = 0.101409, antiderivative size = 81, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05 \[ \frac{2 (-a B e-A b e+2 b B d)}{3 e^3 (d+e x)^{3/2}}-\frac{2 (b d-a e) (B d-A e)}{5 e^3 (d+e x)^{5/2}}-\frac{2 b B}{e^3 \sqrt{d+e x}} \]
Antiderivative was successfully verified.
[In] Int[((a + b*x)*(A + B*x))/(d + e*x)^(7/2),x]
[Out]
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Rubi in Sympy [A] time = 16.6884, size = 80, normalized size = 0.99 \[ - \frac{2 B b}{e^{3} \sqrt{d + e x}} - \frac{2 \left (A b e + B a e - 2 B b d\right )}{3 e^{3} \left (d + e x\right )^{\frac{3}{2}}} - \frac{2 \left (A e - B d\right ) \left (a e - b d\right )}{5 e^{3} \left (d + e x\right )^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)*(B*x+A)/(e*x+d)**(7/2),x)
[Out]
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Mathematica [A] time = 0.0873675, size = 68, normalized size = 0.84 \[ -\frac{2 \left (a e (3 A e+2 B d+5 B e x)+A b e (2 d+5 e x)+b B \left (8 d^2+20 d e x+15 e^2 x^2\right )\right )}{15 e^3 (d+e x)^{5/2}} \]
Antiderivative was successfully verified.
[In] Integrate[((a + b*x)*(A + B*x))/(d + e*x)^(7/2),x]
[Out]
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Maple [A] time = 0.006, size = 73, normalized size = 0.9 \[ -{\frac{30\,bB{x}^{2}{e}^{2}+10\,Ab{e}^{2}x+10\,Ba{e}^{2}x+40\,Bbdex+6\,aA{e}^{2}+4\,Abde+4\,Bade+16\,bB{d}^{2}}{15\,{e}^{3}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)*(B*x+A)/(e*x+d)^(7/2),x)
[Out]
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Maxima [A] time = 1.39192, size = 97, normalized size = 1.2 \[ -\frac{2 \,{\left (15 \,{\left (e x + d\right )}^{2} B b + 3 \, B b d^{2} + 3 \, A a e^{2} - 3 \,{\left (B a + A b\right )} d e - 5 \,{\left (2 \, B b d -{\left (B a + A b\right )} e\right )}{\left (e x + d\right )}\right )}}{15 \,{\left (e x + d\right )}^{\frac{5}{2}} e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(b*x + a)/(e*x + d)^(7/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.227252, size = 122, normalized size = 1.51 \[ -\frac{2 \,{\left (15 \, B b e^{2} x^{2} + 8 \, B b d^{2} + 3 \, A a e^{2} + 2 \,{\left (B a + A b\right )} d e + 5 \,{\left (4 \, B b d e +{\left (B a + A b\right )} e^{2}\right )} x\right )}}{15 \,{\left (e^{5} x^{2} + 2 \, d e^{4} x + d^{2} e^{3}\right )} \sqrt{e x + d}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(b*x + a)/(e*x + d)^(7/2),x, algorithm="fricas")
[Out]
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Sympy [A] time = 9.28145, size = 520, normalized size = 6.42 \[ \begin{cases} - \frac{6 A a e^{2}}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{4 A b d e}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{10 A b e^{2} x}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{4 B a d e}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{10 B a e^{2} x}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{16 B b d^{2}}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{40 B b d e x}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} - \frac{30 B b e^{2} x^{2}}{15 d^{2} e^{3} \sqrt{d + e x} + 30 d e^{4} x \sqrt{d + e x} + 15 e^{5} x^{2} \sqrt{d + e x}} & \text{for}\: e \neq 0 \\\frac{A a x + \frac{A b x^{2}}{2} + \frac{B a x^{2}}{2} + \frac{B b x^{3}}{3}}{d^{\frac{7}{2}}} & \text{otherwise} \end{cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)*(B*x+A)/(e*x+d)**(7/2),x)
[Out]
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GIAC/XCAS [A] time = 0.215903, size = 117, normalized size = 1.44 \[ -\frac{2 \,{\left (15 \,{\left (x e + d\right )}^{2} B b - 10 \,{\left (x e + d\right )} B b d + 3 \, B b d^{2} + 5 \,{\left (x e + d\right )} B a e + 5 \,{\left (x e + d\right )} A b e - 3 \, B a d e - 3 \, A b d e + 3 \, A a e^{2}\right )} e^{\left (-3\right )}}{15 \,{\left (x e + d\right )}^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(b*x + a)/(e*x + d)^(7/2),x, algorithm="giac")
[Out]